What are the solutions to the equation (1+x/2)^2=(1+(0.08)/4)^4 ?

The solutions to the equation (1+x/2)^2=(1+(0.08)/4)^4 are x=0.0808,x=-4.0808

Find the zeros of (1+x/2)^2=(1+(0.08)/4)^4

The zeros of (1+x/2)^2=(1+(0.08)/4)^4 are x=0.0808,x=-4.0808

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(1 + \frac{x}{2})^{2} = (1 + \frac{0.08}{4})^{4}

x = 0.0808, x = - 4.0808

Solution steps

(1 + \frac{x}{2})^{2} = (1 + \frac{0.08}{4})^{4}

Simplify

(1 + \frac{0.08}{4})^{4} : \frac{277.10263 \dots}{256}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 + \frac{x}{2} = \frac{277.10263 \dots}{256} : x = 0.0808

Solve

1 + \frac{x}{2} = - \frac{277.10263 \dots}{256} : x = - 4.0808

The solutions to the quadratic equation are:

x = 0.0808, x = - 4.0808

x^{2} + 2 x + 5 = 2 x + 5

30 u = 9 u^{2} + 25

3^{2} + x^{2} = 13^{2}

x^{2} - 15 x = 0

x^{2} - 2 x + 0.5 = 0

What are the solutions to the equation (1+x/2)^2=(1+(0.08)/4)^4 ?
The solutions to the equation (1+x/2)^2=(1+(0.08)/4)^4 are x=0.0808,x=-4.0808
Find the zeros of (1+x/2)^2=(1+(0.08)/4)^4
The zeros of (1+x/2)^2=(1+(0.08)/4)^4 are x=0.0808,x=-4.0808