What are the solutions to the equation 2n^2-18n=-40 ?

The solutions to the equation 2n^2-18n=-40 are n=5,n=4

Find the zeros of 2n^2-18n=-40

The zeros of 2n^2-18n=-40 are n=5,n=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 n^{2} - 18 n = - 40

n = 5, n = 4

Solution steps

2 n^{2} - 18 n = - 40

Move

40

to the left side

2 n^{2} - 18 n + 40 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 2 \cdot 40}{2 \cdot 2}

(- 18)^{2} - 4 \cdot 2 \cdot 40 = 2

n_{1, 2} = \frac{- ( - 18 ) \pm 2}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- ( - 18 ) + 2}{2 \cdot 2}, n_{2} = \frac{- ( - 18 ) - 2}{2 \cdot 2}

n = \frac{- ( - 18 ) + 2}{2 \cdot 2} : 5

n = \frac{- ( - 18 ) - 2}{2 \cdot 2} : 4

The solutions to the quadratic equation are:

n = 5, n = 4

- 4 x^{2} - 2 x - 1 = 0

y, \frac{y ^{2}}{a ^{2}} + \frac{x ^{2}}{b ^{2}} = 1

1.163 x^{2} - 4.44 x = 0

x, x^{2} + 5.35 x + 9.125 = 0

x^{2} - 4 x + 25 = 0

What are the solutions to the equation 2n^2-18n=-40 ?
The solutions to the equation 2n^2-18n=-40 are n=5,n=4
Find the zeros of 2n^2-18n=-40
The zeros of 2n^2-18n=-40 are n=5,n=4