What are the solutions to the equation 2k^2+16k=-12 ?

The solutions to the equation 2k^2+16k=-12 are k=-4+sqrt(10),k=-4-sqrt(10)

Find the zeros of 2k^2+16k=-12

The zeros of 2k^2+16k=-12 are k=-4+sqrt(10),k=-4-sqrt(10)

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2 k^{2} + 16 k = - 12

k = - 4 + 10, k = - 4 - 10

Decimal Notation

k = - 0.83772 \dots, k = - 7.16227 \dots

Solution steps

2 k^{2} + 16 k = - 12

Move

12

to the left side

2 k^{2} + 16 k + 12 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

1 6^{2} - 4 \cdot 2 \cdot 12 = 410

k_{1, 2} = \frac{- 16 \pm 4 10}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 16 + 4 10}{2 \cdot 2}, k_{2} = \frac{- 16 - 4 10}{2 \cdot 2}

k = \frac{- 16 + 4 10}{2 \cdot 2} : - 4 + 10

k = \frac{- 16 - 4 10}{2 \cdot 2} : - 4 - 10

The solutions to the quadratic equation are:

k = - 4 + 10, k = - 4 - 10

1 - x = 1 - x^{2}

36 x^{2} + 72 = 0

b^{2} + b - 30 = 0

4 w^{2} - 44 w + 121 = 0

2 t^{2} + 18 t = - 4

What are the solutions to the equation 2k^2+16k=-12 ?
The solutions to the equation 2k^2+16k=-12 are k=-4+sqrt(10),k=-4-sqrt(10)
Find the zeros of 2k^2+16k=-12
The zeros of 2k^2+16k=-12 are k=-4+sqrt(10),k=-4-sqrt(10)