What are the solutions to the equation 3x^2+21=0 ?

The solutions to the equation 3x^2+21=0 are x=sqrt(7)i,x=-sqrt(7)i

Find the zeros of 3x^2+21=0

The zeros of 3x^2+21=0 are x=sqrt(7)i,x=-sqrt(7)i

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3 x^{2} + 21 = 0

x = 7 i, x = - 7 i

Solution steps

3 x^{2} + 21 = 0

Move

21

to the right side

3 x^{2} = - 21

Divide both sides by

3

x^{2} = - 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 7, x = - - 7

- 7 = 7 i

- - 7 = - 7 i

x = 7 i, x = - 7 i

35 m^{2} n^{3} - 70 m^{3}

3 = 2 + \frac{v}{14}

2^{\frac{3}{2}}

12 x^{4} - 16 x^{3} - 41 x^{2} + 69 x - 18 > 0

What are the solutions to the equation 3x^2+21=0 ?
The solutions to the equation 3x^2+21=0 are x=sqrt(7)i,x=-sqrt(7)i
Find the zeros of 3x^2+21=0
The zeros of 3x^2+21=0 are x=sqrt(7)i,x=-sqrt(7)i