What are the solutions to the equation -16x^2+272x+204=0 ?

The solutions to the equation -16x^2+272x+204=0 are x=-(-17+2sqrt(85))/2 ,x=(17+2sqrt(85))/2

Find the zeros of -16x^2+272x+204=0

The zeros of -16x^2+272x+204=0 are x=-(-17+2sqrt(85))/2 ,x=(17+2sqrt(85))/2

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- 16 x^{2} + 272 x + 204 = 0

x = - \frac{- 17 + 2 85}{2}, x = \frac{17 + 2 85}{2}

Decimal Notation

x = - 0.71954 \dots, x = 17.71954 \dots

Solution steps

- 16 x^{2} + 272 x + 204 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 272 \pm 27 2 ^{2} - 4 ( - 16 ) \cdot 204}{2 ( - 16 )}

27 2^{2} - 4 (- 16) \cdot 204 = 3285

x_{1, 2} = \frac{- 272 \pm 32 85}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 272 + 32 85}{2 ( - 16 )}, x_{2} = \frac{- 272 - 32 85}{2 ( - 16 )}

x = \frac{- 272 + 32 85}{2 ( - 16 )} : - \frac{- 17 + 2 85}{2}

x = \frac{- 272 - 32 85}{2 ( - 16 )} : \frac{17 + 2 85}{2}

The solutions to the quadratic equation are:

x = - \frac{- 17 + 2 85}{2}, x = \frac{17 + 2 85}{2}

x, 26406.25 = (25 - 2 x) (1000 + 50 x)

y^{2} + 7 y + 6 = 0

3 (x + 5)^{2} = 0

2 n^{2} - 11 n - 13 = 0

b^{2} + 5 b = 0

What are the solutions to the equation -16x^2+272x+204=0 ?
The solutions to the equation -16x^2+272x+204=0 are x=-(-17+2sqrt(85))/2 ,x=(17+2sqrt(85))/2
Find the zeros of -16x^2+272x+204=0
The zeros of -16x^2+272x+204=0 are x=-(-17+2sqrt(85))/2 ,x=(17+2sqrt(85))/2