What are the solutions to the equation 2x^2+(5-x)+x=11 ?

The solutions to the equation 2x^2+(5-x)+x=11 are x=sqrt(3),x=-sqrt(3)

Find the zeros of 2x^2+(5-x)+x=11

The zeros of 2x^2+(5-x)+x=11 are x=sqrt(3),x=-sqrt(3)

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2 x^{2} + (5 - x) + x = 11

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

2 x^{2} + (5 - x) + x = 11

Refine

2 x^{2} + 5 = 11

Move

11

to the left side

2 x^{2} - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

0^{2} - 4 \cdot 2 (- 6) = 43

x_{1, 2} = \frac{- 0 \pm 4 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 4 3}{2 \cdot 2}, x_{2} = \frac{- 0 - 4 3}{2 \cdot 2}

x = \frac{- 0 + 4 3}{2 \cdot 2} : 3

x = \frac{- 0 - 4 3}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = 3, x = - 3

6 b^{2} - 3 b - 18 = 0

(x - 3)^{2} + 1 = 0

x^{2} = - 6 x + 8

5 (x + 2) (2 x - 1) = 0

2 x^{2} + 2 x + 7 = 0

What are the solutions to the equation 2x^2+(5-x)+x=11 ?
The solutions to the equation 2x^2+(5-x)+x=11 are x=sqrt(3),x=-sqrt(3)
Find the zeros of 2x^2+(5-x)+x=11
The zeros of 2x^2+(5-x)+x=11 are x=sqrt(3),x=-sqrt(3)