What are the solutions to the equation 20x^2-7x-3=0 ?

The solutions to the equation 20x^2-7x-3=0 are x= 3/5 ,x=-1/4

Find the zeros of 20x^2-7x-3=0

The zeros of 20x^2-7x-3=0 are x= 3/5 ,x=-1/4

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20 x^{2} - 7 x - 3 = 0

x = \frac{3}{5}, x = - \frac{1}{4}

Decimal Notation

x = 0.6, x = - 0.25

Solution steps

20 x^{2} - 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 20 ( - 3 )}{2 \cdot 20}

(- 7)^{2} - 4 \cdot 20 (- 3) = 17

x_{1, 2} = \frac{- ( - 7 ) \pm 17}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 17}{2 \cdot 20}, x_{2} = \frac{- ( - 7 ) - 17}{2 \cdot 20}

x = \frac{- ( - 7 ) + 17}{2 \cdot 20} : \frac{3}{5}

x = \frac{- ( - 7 ) - 17}{2 \cdot 20} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - \frac{1}{4}

50 x^{2} = 18

x, z = 3 x^{2} - 12 x + 2 y^{3} + 3 y^{2} - 12 y

0 = 18 x^{2} - 18 x - 108

y^{2} = \frac{1}{4}

3 w^{2} + 15 w = 0

What are the solutions to the equation 20x^2-7x-3=0 ?
The solutions to the equation 20x^2-7x-3=0 are x= 3/5 ,x=-1/4
Find the zeros of 20x^2-7x-3=0
The zeros of 20x^2-7x-3=0 are x= 3/5 ,x=-1/4