What are the solutions to the equation m^2+3m+6=0 ?

The solutions to the equation m^2+3m+6=0 are m=-3/2+i(sqrt(15))/2 ,m=-3/2-i(sqrt(15))/2

Find the zeros of m^2+3m+6=0

The zeros of m^2+3m+6=0 are m=-3/2+i(sqrt(15))/2 ,m=-3/2-i(sqrt(15))/2

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m^{2} + 3 m + 6 = 0

m = - \frac{3}{2} + i \frac{15}{2}, m = - \frac{3}{2} - i \frac{15}{2}

Solution steps

m^{2} + 3 m + 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 6 : 15 i

m_{1, 2} = \frac{- 3 \pm 15 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 3 + 15 i}{2 \cdot 1}, m_{2} = \frac{- 3 - 15 i}{2 \cdot 1}

m = \frac{- 3 + 15 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{15}{2}

m = \frac{- 3 - 15 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

m = - \frac{3}{2} + i \frac{15}{2}, m = - \frac{3}{2} - i \frac{15}{2}

V, P = \frac{V ^{2}}{R}

3 y^{2} - 36 = 0

x^{2} + 2 x = 143

4 x - x^{2} = 2 x - 3

6 y^{2} + 18 y = 0

What are the solutions to the equation m^2+3m+6=0 ?
The solutions to the equation m^2+3m+6=0 are m=-3/2+i(sqrt(15))/2 ,m=-3/2-i(sqrt(15))/2
Find the zeros of m^2+3m+6=0
The zeros of m^2+3m+6=0 are m=-3/2+i(sqrt(15))/2 ,m=-3/2-i(sqrt(15))/2