What are the solutions to the equation 24^2=12^2+x^2 ?

The solutions to the equation 24^2=12^2+x^2 are x=12sqrt(3),x=-12sqrt(3)

Find the zeros of 24^2=12^2+x^2

The zeros of 24^2=12^2+x^2 are x=12sqrt(3),x=-12sqrt(3)

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2 4^{2} = 1 2^{2} + x^{2}

x = 123, x = - 123

Decimal Notation

x = 20.78460 \dots, x = - 20.78460 \dots

Solution steps

2 4^{2} = 1 2^{2} + x^{2}

Switch sides

1 2^{2} + x^{2} = 2 4^{2}

Move

1 2^{2}

to the right side

x^{2} = 432

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 432, x = - 432

432 = 123

- 432 = - 123

x = 123, x = - 123

s, s^{2} + 4 s + 5 = 0

(30 + x) \cdot (30 + x) = 1660

x \cdot x + 1 \cdot x + 2 = (x + 1) 80

x^{2} + 160 x + 10000 = 0

x, 3 x^{2} - 4 x + 2 = 0

What are the solutions to the equation 24^2=12^2+x^2 ?
The solutions to the equation 24^2=12^2+x^2 are x=12sqrt(3),x=-12sqrt(3)
Find the zeros of 24^2=12^2+x^2
The zeros of 24^2=12^2+x^2 are x=12sqrt(3),x=-12sqrt(3)