What are the solutions to the equation 2x^2+5x-8= 5/2 x+20 ?

The solutions to the equation 2x^2+5x-8= 5/2 x+20 are x=(-5+sqrt(921))/8 ,x=(-5-sqrt(921))/8

Find the zeros of 2x^2+5x-8= 5/2 x+20

The zeros of 2x^2+5x-8= 5/2 x+20 are x=(-5+sqrt(921))/8 ,x=(-5-sqrt(921))/8

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2 x^{2} + 5 x - 8 = \frac{5}{2} x + 20

x = \frac{- 5 + 921}{8}, x = \frac{- 5 - 921}{8}

Decimal Notation

x = 3.16849 \dots, x = - 4.41849 \dots

Solution steps

2 x^{2} + 5 x - 8 = \frac{5}{2} x + 20

Multiply both sides by

2

4 x^{2} + 10 x - 16 = 5 x + 40

Move

40

to the left side

4 x^{2} + 10 x - 56 = 5 x

Move

5 x

to the left side

4 x^{2} + 5 x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 56 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 56) = 921

x_{1, 2} = \frac{- 5 \pm 921}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 921}{2 \cdot 4}, x_{2} = \frac{- 5 - 921}{2 \cdot 4}

x = \frac{- 5 + 921}{2 \cdot 4} : \frac{- 5 + 921}{8}

x = \frac{- 5 - 921}{2 \cdot 4} : \frac{- 5 - 921}{8}

The solutions to the quadratic equation are:

x = \frac{- 5 + 921}{8}, x = \frac{- 5 - 921}{8}

x^{2} - 28 x + 16 = 0

9 x^{(2)} - 6 x - 11 = 0

x^{2} - 6 x + 5 = 117

5 x^{2} + 32 x + 27 = 0

x^{2} + 4000 x - 12000000 = 0

What are the solutions to the equation 2x^2+5x-8= 5/2 x+20 ?
The solutions to the equation 2x^2+5x-8= 5/2 x+20 are x=(-5+sqrt(921))/8 ,x=(-5-sqrt(921))/8
Find the zeros of 2x^2+5x-8= 5/2 x+20
The zeros of 2x^2+5x-8= 5/2 x+20 are x=(-5+sqrt(921))/8 ,x=(-5-sqrt(921))/8