What are the solutions to the equation 6X+X(X-13)=18 ?

The solutions to the equation 6X+X(X-13)=18 are X=9,X=-2

Find the zeros of 6X+X(X-13)=18

The zeros of 6X+X(X-13)=18 are X=9,X=-2

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6 X + X (X - 13) = 18

X = 9, X = - 2

Solution steps

6 X + X (X - 13) = 18

Expand

6 X + X (X - 13) : X^{2} - 7 X

X^{2} - 7 X = 18

Move

18

to the left side

X^{2} - 7 X - 18 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 18) = 11

X_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 1}, X_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 1}

X = \frac{- ( - 7 ) + 11}{2 \cdot 1} : 9

X = \frac{- ( - 7 ) - 11}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

X = 9, X = - 2

y^{2} + y = 4

9^{2} + 1 8^{2} = x^{2}

x (x - 5) = 9

x (x - 5) = 4

x (x - 5) = 2

What are the solutions to the equation 6X+X(X-13)=18 ?
The solutions to the equation 6X+X(X-13)=18 are X=9,X=-2
Find the zeros of 6X+X(X-13)=18
The zeros of 6X+X(X-13)=18 are X=9,X=-2