What are the solutions to the equation (x+4)^2+50=0 ?

The solutions to the equation (x+4)^2+50=0 are x=5sqrt(2)i-4,x=-5sqrt(2)i-4

Find the zeros of (x+4)^2+50=0

The zeros of (x+4)^2+50=0 are x=5sqrt(2)i-4,x=-5sqrt(2)i-4

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(x + 4)^{2} + 50 = 0

x = 52 i - 4, x = - 52 i - 4

Solution steps

(x + 4)^{2} + 50 = 0

Move

50

to the right side

(x + 4)^{2} = - 50

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = - 50 : x = 52 i - 4

Solve

x + 4 = - - 50 : x = - 52 i - 4

The solutions to the quadratic equation are:

x = 52 i - 4, x = - 52 i - 4

k^{2} - 7 k + 6 = 0

(- 1 - x) (5 - x) + 9 = 0

5 (2 x^{2} + 32) = 0

x, 8 x^{2} - 8 x = (4 y - 7)^{3}

x^{2} + 6 x + 8 = 4 x - 3

What are the solutions to the equation (x+4)^2+50=0 ?
The solutions to the equation (x+4)^2+50=0 are x=5sqrt(2)i-4,x=-5sqrt(2)i-4
Find the zeros of (x+4)^2+50=0
The zeros of (x+4)^2+50=0 are x=5sqrt(2)i-4,x=-5sqrt(2)i-4