What are the solutions to the equation a^2+8a+15=0 ?

The solutions to the equation a^2+8a+15=0 are a=-3,a=-5

Find the zeros of a^2+8a+15=0

The zeros of a^2+8a+15=0 are a=-3,a=-5

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a^{2} + 8 a + 15 = 0

a = - 3, a = - 5

Solution steps

a^{2} + 8 a + 15 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

a_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 8 + 2}{2 \cdot 1}, a_{2} = \frac{- 8 - 2}{2 \cdot 1}

a = \frac{- 8 + 2}{2 \cdot 1} : - 3

a = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

a = - 3, a = - 5

- 35 = 16 x - 3 x^{2}

7 x^{2} - 7 x - 6 = 6 x^{2} - x + 1

x^{2} - 4 \times + 4 = 0

6 x - 2 x^{2} = 0

x^{2} + 3 x - 10 = 0

What are the solutions to the equation a^2+8a+15=0 ?
The solutions to the equation a^2+8a+15=0 are a=-3,a=-5
Find the zeros of a^2+8a+15=0
The zeros of a^2+8a+15=0 are a=-3,a=-5