What are the solutions to the equation 80+x^2=18x ?

The solutions to the equation 80+x^2=18x are x=10,x=8

Find the zeros of 80+x^2=18x

The zeros of 80+x^2=18x are x=10,x=8

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80 + x^{2} = 18 x

x = 10, x = 8

Solution steps

80 + x^{2} = 18 x

Move

18 x

to the left side

80 + x^{2} - 18 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 18 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 80}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 80 = 2

x_{1, 2} = \frac{- ( - 18 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2}{2 \cdot 1} : 10

x = \frac{- ( - 18 ) - 2}{2 \cdot 1} : 8

The solutions to the quadratic equation are:

x = 10, x = 8

2 < \frac{4 - x}{3} < 6

9 d - 5 = 49

(\frac{1}{x ^{3}})^{2}

∣ x + 1 ∣ > 7

\frac{3 \cdot 1 0 ^{8}}{400 \cdot 1 0 ^{- 9}}

What are the solutions to the equation 80+x^2=18x ?
The solutions to the equation 80+x^2=18x are x=10,x=8
Find the zeros of 80+x^2=18x
The zeros of 80+x^2=18x are x=10,x=8