What are the solutions to the equation 5^2+b^2=11^2 ?

The solutions to the equation 5^2+b^2=11^2 are b=4sqrt(6),b=-4sqrt(6)

Find the zeros of 5^2+b^2=11^2

The zeros of 5^2+b^2=11^2 are b=4sqrt(6),b=-4sqrt(6)

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5^{2} + b^{2} = 1 1^{2}

b = 46, b = - 46

Decimal Notation

b = 9.79795 \dots, b = - 9.79795 \dots

Solution steps

5^{2} + b^{2} = 1 1^{2}

Move

5^{2}

to the right side

b^{2} = 96

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 96, b = - 96

96 = 46

- 96 = - 46

b = 46, b = - 46

x^{2} - 100 x - 400 = 0

r^{2} - 3 r + \frac{9}{4} = 0

s^{2} - 4 s + 8

x (3 - x) = 0

\frac{- x ^{2}}{5} + 15 = 0

What are the solutions to the equation 5^2+b^2=11^2 ?
The solutions to the equation 5^2+b^2=11^2 are b=4sqrt(6),b=-4sqrt(6)
Find the zeros of 5^2+b^2=11^2
The zeros of 5^2+b^2=11^2 are b=4sqrt(6),b=-4sqrt(6)