What are the solutions to the equation 19x^2-23x+5=0 ?

The solutions to the equation 19x^2-23x+5=0 are x=(23+sqrt(149))/(38),x=(23-sqrt(149))/(38)

Find the zeros of 19x^2-23x+5=0

The zeros of 19x^2-23x+5=0 are x=(23+sqrt(149))/(38),x=(23-sqrt(149))/(38)

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19 x^{2} - 23 x + 5 = 0

x = \frac{23 + 149}{38}, x = \frac{23 - 149}{38}

Decimal Notation

x = 0.92648 \dots, x = 0.28403 \dots

Solution steps

19 x^{2} - 23 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 19 \cdot 5}{2 \cdot 19}

(- 23)^{2} - 4 \cdot 19 \cdot 5 = 149

x_{1, 2} = \frac{- ( - 23 ) \pm 149}{2 \cdot 19}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 149}{2 \cdot 19}, x_{2} = \frac{- ( - 23 ) - 149}{2 \cdot 19}

x = \frac{- ( - 23 ) + 149}{2 \cdot 19} : \frac{23 + 149}{38}

x = \frac{- ( - 23 ) - 149}{2 \cdot 19} : \frac{23 - 149}{38}

The solutions to the quadratic equation are:

x = \frac{23 + 149}{38}, x = \frac{23 - 149}{38}

d, (d + 1)^{2} y = 0

x^{2} - 6 x + 8 x = 0

\frac{x ^{2}}{2} - 2 x + 1 = 0

x^{2} + 5 x - 49 = 0

- 16 x^{2} + 64 x = 0

What are the solutions to the equation 19x^2-23x+5=0 ?
The solutions to the equation 19x^2-23x+5=0 are x=(23+sqrt(149))/(38),x=(23-sqrt(149))/(38)
Find the zeros of 19x^2-23x+5=0
The zeros of 19x^2-23x+5=0 are x=(23+sqrt(149))/(38),x=(23-sqrt(149))/(38)