What are the solutions to the equation 4x^2+4x^2=36 ?

The solutions to the equation 4x^2+4x^2=36 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

Find the zeros of 4x^2+4x^2=36

The zeros of 4x^2+4x^2=36 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

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4 x^{2} + 4 x^{2} = 36

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 2.12132 \dots, x = - 2.12132 \dots

Solution steps

4 x^{2} + 4 x^{2} = 36

Add similar elements:

4 x^{2} + 4 x^{2} = 8 x^{2}

8 x^{2} = 36

Divide both sides by

8

x^{2} = \frac{9}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{2}, x = - \frac{9}{2}

\frac{9}{2} = \frac{3}{2}

- \frac{9}{2} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

x^{2} - 6 x = 16

(5 p + 3)^{2} = 12

x^{2} + 6 x = 5, x < - 1

7 x^{2} - 22 x + 3 = 0

x^{2} + (k - 3) x - k = 0

What are the solutions to the equation 4x^2+4x^2=36 ?
The solutions to the equation 4x^2+4x^2=36 are x= 3/(sqrt(2)),x=-3/(sqrt(2))
Find the zeros of 4x^2+4x^2=36
The zeros of 4x^2+4x^2=36 are x= 3/(sqrt(2)),x=-3/(sqrt(2))