What are the solutions to the equation 3x^2-5x-13=0 ?

The solutions to the equation 3x^2-5x-13=0 are x=(5+sqrt(181))/6 ,x=(5-sqrt(181))/6

Find the zeros of 3x^2-5x-13=0

The zeros of 3x^2-5x-13=0 are x=(5+sqrt(181))/6 ,x=(5-sqrt(181))/6

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3 x^{2} - 5 x - 13 = 0

x = \frac{5 + 181}{6}, x = \frac{5 - 181}{6}

Decimal Notation

x = 3.07560 \dots, x = - 1.40893 \dots

Solution steps

3 x^{2} - 5 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 13 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 13) = 181

x_{1, 2} = \frac{- ( - 5 ) \pm 181}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 181}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 181}{2 \cdot 3}

x = \frac{- ( - 5 ) + 181}{2 \cdot 3} : \frac{5 + 181}{6}

x = \frac{- ( - 5 ) - 181}{2 \cdot 3} : \frac{5 - 181}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 181}{6}, x = \frac{5 - 181}{6}

x, z = x^{2} - 4 x y - 2 y^{2} + 12 x - 12 y - 1

6 x^{2} - 108 = 0

w^{2} - 84 = 0

3 x (x - 1) = 0

x^{2} - 5 x = 0

What are the solutions to the equation 3x^2-5x-13=0 ?
The solutions to the equation 3x^2-5x-13=0 are x=(5+sqrt(181))/6 ,x=(5-sqrt(181))/6
Find the zeros of 3x^2-5x-13=0
The zeros of 3x^2-5x-13=0 are x=(5+sqrt(181))/6 ,x=(5-sqrt(181))/6