What are the solutions to the equation -x^2-18x-81=0 ?

The solutions to the equation -x^2-18x-81=0 are x=-9

Find the zeros of -x^2-18x-81=0

The zeros of -x^2-18x-81=0 are x=-9

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- x^{2} - 18 x - 81 = 0

x = - 9

Solution steps

- x^{2} - 18 x - 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 ( - 1 ) ( - 81 )}{2 ( - 1 )}

(- 18)^{2} - 4 (- 1) (- 81) = 0

x_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 18 )}{2 ( - 1 )}

\frac{- ( - 18 )}{2 ( - 1 )} = - 9

x = - 9

The solution to the quadratic equation is:

x = - 9

t, (t - h)^{2} = \frac{8}{5}

x^{0} + x^{2} = 10

(1 - x) (3 - x) - 1 = 0

\frac{1}{2} x^{2} = 36 - 3 x

(x - 9) (x - 8) = 0

What are the solutions to the equation -x^2-18x-81=0 ?
The solutions to the equation -x^2-18x-81=0 are x=-9
Find the zeros of -x^2-18x-81=0
The zeros of -x^2-18x-81=0 are x=-9