What are the solutions to the equation k^2+24k+144=0 ?

The solutions to the equation k^2+24k+144=0 are k=-12

Find the zeros of k^2+24k+144=0

The zeros of k^2+24k+144=0 are k=-12

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k^{2} + 24 k + 144 = 0

k = - 12

Solution steps

k^{2} + 24 k + 144 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot 144}{2 \cdot 1}

2 4^{2} - 4 \cdot 1 \cdot 144 = 0

k_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 1}

k = \frac{- 24}{2 \cdot 1}

\frac{- 24}{2 \cdot 1} = - 12

k = - 12

The solution to the quadratic equation is:

k = - 12

x, x^{2} y^{2} - 9 x^{2} - 4 y^{2} = 0

x^{2} + 15 x - 5 = 0

(2 x + 1) (x - 1) = 9

x^{2} - 14 x + 49 = 18

(x + 8)^{2} = 7

What are the solutions to the equation k^2+24k+144=0 ?
The solutions to the equation k^2+24k+144=0 are k=-12
Find the zeros of k^2+24k+144=0
The zeros of k^2+24k+144=0 are k=-12