What are the solutions to the equation 3r^2-16r-2=0 ?

The solutions to the equation 3r^2-16r-2=0 are r=(8+sqrt(70))/3 ,r=(8-sqrt(70))/3

Find the zeros of 3r^2-16r-2=0

The zeros of 3r^2-16r-2=0 are r=(8+sqrt(70))/3 ,r=(8-sqrt(70))/3

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3 r^{2} - 16 r - 2 = 0

r = \frac{8 + 70}{3}, r = \frac{8 - 70}{3}

Decimal Notation

r = 5.45553 \dots, r = - 0.12220 \dots

Solution steps

3 r^{2} - 16 r - 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 (- 2) = 270

r_{1, 2} = \frac{- ( - 16 ) \pm 2 70}{2 \cdot 3}

Separate the solutions

r_{1} = \frac{- ( - 16 ) + 2 70}{2 \cdot 3}, r_{2} = \frac{- ( - 16 ) - 2 70}{2 \cdot 3}

r = \frac{- ( - 16 ) + 2 70}{2 \cdot 3} : \frac{8 + 70}{3}

r = \frac{- ( - 16 ) - 2 70}{2 \cdot 3} : \frac{8 - 70}{3}

The solutions to the quadratic equation are:

r = \frac{8 + 70}{3}, r = \frac{8 - 70}{3}

2 x^{2} - 21 x + 40 = 0

x^{2} - 5.1 x + 6.3 = 0

\frac{x ^{2}}{3} = 4 x - x^{2}

(x - 2) (x - 6) = 5

4 h^{2} - 9 = 0

What are the solutions to the equation 3r^2-16r-2=0 ?
The solutions to the equation 3r^2-16r-2=0 are r=(8+sqrt(70))/3 ,r=(8-sqrt(70))/3
Find the zeros of 3r^2-16r-2=0
The zeros of 3r^2-16r-2=0 are r=(8+sqrt(70))/3 ,r=(8-sqrt(70))/3