What are the solutions to the equation 12x^2+8x+1=0 ?

The solutions to the equation 12x^2+8x+1=0 are x=-1/6 ,x=-1/2

Find the zeros of 12x^2+8x+1=0

The zeros of 12x^2+8x+1=0 are x=-1/6 ,x=-1/2

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12 x^{2} + 8 x + 1 = 0

x = - \frac{1}{6}, x = - \frac{1}{2}

Decimal Notation

x = - 0.16666 \dots, x = - 0.5

Solution steps

12 x^{2} + 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 12 \cdot 1}{2 \cdot 12}

8^{2} - 4 \cdot 12 \cdot 1 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 12}, x_{2} = \frac{- 8 - 4}{2 \cdot 12}

x = \frac{- 8 + 4}{2 \cdot 12} : - \frac{1}{6}

x = \frac{- 8 - 4}{2 \cdot 12} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{6}, x = - \frac{1}{2}

x, x^{2} + 45 k^{2} = 18 k x

x, 2 x^{2} + 12 x + 4 = 0

m^{2} + 40 m + 4000 = 0

c^{2} + 10 c + 8 = 0

4 z^{2} - 5 z + 3 = 0

What are the solutions to the equation 12x^2+8x+1=0 ?
The solutions to the equation 12x^2+8x+1=0 are x=-1/6 ,x=-1/2
Find the zeros of 12x^2+8x+1=0
The zeros of 12x^2+8x+1=0 are x=-1/6 ,x=-1/2