What are the solutions to the equation 0=-16t^2+32t+28 ?

The solutions to the equation 0=-16t^2+32t+28 are t=-(-2+sqrt(11))/2 ,t=(2+sqrt(11))/2

Find the zeros of 0=-16t^2+32t+28

The zeros of 0=-16t^2+32t+28 are t=-(-2+sqrt(11))/2 ,t=(2+sqrt(11))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 16 t^{2} + 32 t + 28

t = - \frac{- 2 + 11}{2}, t = \frac{2 + 11}{2}

Decimal Notation

t = - 0.65831 \dots, t = 2.65831 \dots

Solution steps

0 = - 16 t^{2} + 32 t + 28

Switch sides

- 16 t^{2} + 32 t + 28 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 16 ) \cdot 28}{2 ( - 16 )}

3 2^{2} - 4 (- 16) \cdot 28 = 1611

t_{1, 2} = \frac{- 32 \pm 16 11}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 32 + 16 11}{2 ( - 16 )}, t_{2} = \frac{- 32 - 16 11}{2 ( - 16 )}

t = \frac{- 32 + 16 11}{2 ( - 16 )} : - \frac{- 2 + 11}{2}

t = \frac{- 32 - 16 11}{2 ( - 16 )} : \frac{2 + 11}{2}

The solutions to the quadratic equation are:

t = - \frac{- 2 + 11}{2}, t = \frac{2 + 11}{2}

x, x^{2} - 6 y^{2} = x y

2 x^{2} + 2 x + 10 = 0

3 X^{2} - 24 X + 100 = 60

2 x^{2} + 16 = 12 x

x^{2} - 10 = 30 x

What are the solutions to the equation 0=-16t^2+32t+28 ?
The solutions to the equation 0=-16t^2+32t+28 are t=-(-2+sqrt(11))/2 ,t=(2+sqrt(11))/2
Find the zeros of 0=-16t^2+32t+28
The zeros of 0=-16t^2+32t+28 are t=-(-2+sqrt(11))/2 ,t=(2+sqrt(11))/2