What are the solutions to the equation 4x^2-13+3=0 ?

The solutions to the equation 4x^2-13+3=0 are x=sqrt(5/2),x=-sqrt(5/2)

Find the zeros of 4x^2-13+3=0

The zeros of 4x^2-13+3=0 are x=sqrt(5/2),x=-sqrt(5/2)

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4 x^{2} - 13 + 3 = 0

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 1.58113 \dots, x = - 1.58113 \dots

Solution steps

4 x^{2} - 13 + 3 = 0

Move

13

to the right side

4 x^{2} + 3 = 13

Move

3

to the right side

4 x^{2} = 10

Divide both sides by

4

x^{2} = \frac{5}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{2}, x = - \frac{5}{2}

6 x^{2} + 4 x - 12 = 0

e = \frac{1}{2} m v^{2}

x, \frac{x ^{2}}{4} + y^{2} + \frac{z ^{2}}{9} = 3

12 x^{2} = 108

x, x^{2} - k x + 169 = 0

What are the solutions to the equation 4x^2-13+3=0 ?
The solutions to the equation 4x^2-13+3=0 are x=sqrt(5/2),x=-sqrt(5/2)
Find the zeros of 4x^2-13+3=0
The zeros of 4x^2-13+3=0 are x=sqrt(5/2),x=-sqrt(5/2)