What are the solutions to the equation 4x^2+5=-9x ?

The solutions to the equation 4x^2+5=-9x are x=-1,x=-5/4

Find the zeros of 4x^2+5=-9x

The zeros of 4x^2+5=-9x are x=-1,x=-5/4

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4 x^{2} + 5 = - 9 x

x = - 1, x = - \frac{5}{4}

Decimal Notation

x = - 1, x = - 1.25

Solution steps

4 x^{2} + 5 = - 9 x

Move

9 x

to the left side

4 x^{2} + 5 + 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 9 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

9^{2} - 4 \cdot 4 \cdot 5 = 1

x_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 1}{2 \cdot 4}, x_{2} = \frac{- 9 - 1}{2 \cdot 4}

x = \frac{- 9 + 1}{2 \cdot 4} : - 1

x = \frac{- 9 - 1}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{5}{4}

p^{2} - 4 p - 8 = 0

D, D^{2} y + 3 Dy + 2 y = 15 e^{4 x}

y, 0 = x^{3} + x y^{2} - y^{2}

8 x^{2} - 5 = 251

(x - 9) (x + 2) = 0

What are the solutions to the equation 4x^2+5=-9x ?
The solutions to the equation 4x^2+5=-9x are x=-1,x=-5/4
Find the zeros of 4x^2+5=-9x
The zeros of 4x^2+5=-9x are x=-1,x=-5/4