What is the answer to log_{81}(1/9)=n ?

The answer to log_{81}(1/9)=n is n=-1/2

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log_{81}(1/9)=n

lo g_{81} (\frac{1}{9}) = n

n = - \frac{1}{2}

Decimal Notation

n = - 0.5

Solution steps

lo g_{81} (\frac{1}{9}) = n

Switch sides

n = lo g_{81} (\frac{1}{9})

Simplify

lo g_{81} (\frac{1}{9}) : - \frac{1}{2}

n = - \frac{1}{2}

10 \cdot 14

2 x^{2} + 6 x = - 3

a^{3} b^{2} - 2 a^{3} b

6 a x + 3 a + 1 + 2 x

4 x - 1 \leq 11