What are the solutions to the equation (-2x+5)^2=-8 ?

The solutions to the equation (-2x+5)^2=-8 are x= 5/2-sqrt(2)i,x= 5/2+sqrt(2)i

Find the zeros of (-2x+5)^2=-8

The zeros of (-2x+5)^2=-8 are x= 5/2-sqrt(2)i,x= 5/2+sqrt(2)i

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(- 2 x + 5)^{2} = - 8

x = \frac{5}{2} - 2 i, x = \frac{5}{2} + 2 i

Solution steps

(- 2 x + 5)^{2} = - 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

- 2 x + 5 = - 8 : x = \frac{5}{2} - 2 i

Solve

- 2 x + 5 = - - 8 : x = \frac{5}{2} + 2 i

The solutions to the quadratic equation are:

x = \frac{5}{2} - 2 i, x = \frac{5}{2} + 2 i

12 x^{2} - 488 x + 3321 = 0

x, 4 z^{2} - x^{2} - y + 16 z + 4 z + 20 = 0

6 x^{2} + x - 2 = 0

\frac{3 ( - x + 2 )}{5} + 4 x (\frac{- 2 x + 1}{3}) = x (- 3 x + 1) - \frac{1}{2}

(x + 4) 2 x = (x + 1) (x - 1) - 23

What are the solutions to the equation (-2x+5)^2=-8 ?
The solutions to the equation (-2x+5)^2=-8 are x= 5/2-sqrt(2)i,x= 5/2+sqrt(2)i
Find the zeros of (-2x+5)^2=-8
The zeros of (-2x+5)^2=-8 are x= 5/2-sqrt(2)i,x= 5/2+sqrt(2)i