What are the solutions to the equation solvefor k,x= 1/2 (k^2-1) ?

The solutions to the equation solvefor k,x= 1/2 (k^2-1) are k=sqrt(2x+1),k=-sqrt(2x+1)

Find the zeros of solvefor k,x= 1/2 (k^2-1)

The zeros of solvefor k,x= 1/2 (k^2-1) are k=sqrt(2x+1),k=-sqrt(2x+1)

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solve for

k, x = \frac{1}{2} (k^{2} - 1)

k = 2 x + 1, k = - 2 x + 1

Solution steps

x = \frac{1}{2} (k^{2} - 1)

Switch sides

\frac{1}{2} (k^{2} - 1) = x

Multiply both sides by

2

k^{2} - 1 = 2 x

Move

1

to the right side

k^{2} = 2 x + 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 2 x + 1, k = - 2 x + 1

x^{2} - 9 x + 3

x^{2} - 10 x + 24 = 0

24 x^{2} - 72 x + 48 = 0

x^{2} - 20 x = 10

3^{4} = x^{2}

What are the solutions to the equation solvefor k,x= 1/2 (k^2-1) ?
The solutions to the equation solvefor k,x= 1/2 (k^2-1) are k=sqrt(2x+1),k=-sqrt(2x+1)
Find the zeros of solvefor k,x= 1/2 (k^2-1)
The zeros of solvefor k,x= 1/2 (k^2-1) are k=sqrt(2x+1),k=-sqrt(2x+1)