What are the solutions to the equation 14x^2-60x+50=0 ?

The solutions to the equation 14x^2-60x+50=0 are x=(5(3+sqrt(2)))/7 ,x=(5(3-sqrt(2)))/7

Find the zeros of 14x^2-60x+50=0

The zeros of 14x^2-60x+50=0 are x=(5(3+sqrt(2)))/7 ,x=(5(3-sqrt(2)))/7

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14 x^{2} - 60 x + 50 = 0

x = \frac{5 ( 3 + 2 )}{7}, x = \frac{5 ( 3 - 2 )}{7}

Decimal Notation

x = 3.15300 \dots, x = 1.13270 \dots

Solution steps

14 x^{2} - 60 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 14 \cdot 50}{2 \cdot 14}

(- 60)^{2} - 4 \cdot 14 \cdot 50 = 202

x_{1, 2} = \frac{- ( - 60 ) \pm 20 2}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 60 ) + 20 2}{2 \cdot 14}, x_{2} = \frac{- ( - 60 ) - 20 2}{2 \cdot 14}

x = \frac{- ( - 60 ) + 20 2}{2 \cdot 14} : \frac{5 ( 3 + 2 )}{7}

x = \frac{- ( - 60 ) - 20 2}{2 \cdot 14} : \frac{5 ( 3 - 2 )}{7}

The solutions to the quadratic equation are:

x = \frac{5 ( 3 + 2 )}{7}, x = \frac{5 ( 3 - 2 )}{7}

(x - 3) (x + 3) = - 5 x

x^{2} - 7 x + 10 = 0

a (x) = - x (x - 80)

2 x^{2} + 20 x + 42 = 0

0 = t^{2} - 5 t + 6

What are the solutions to the equation 14x^2-60x+50=0 ?
The solutions to the equation 14x^2-60x+50=0 are x=(5(3+sqrt(2)))/7 ,x=(5(3-sqrt(2)))/7
Find the zeros of 14x^2-60x+50=0
The zeros of 14x^2-60x+50=0 are x=(5(3+sqrt(2)))/7 ,x=(5(3-sqrt(2)))/7