What are the solutions to the equation (x+6)(x+2)=5 ?

The solutions to the equation (x+6)(x+2)=5 are x=-1,x=-7

Find the zeros of (x+6)(x+2)=5

The zeros of (x+6)(x+2)=5 are x=-1,x=-7

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(x + 6) (x + 2) = 5

x = - 1, x = - 7

Solution steps

(x + 6) (x + 2) = 5

Expand

(x + 6) (x + 2) : x^{2} + 8 x + 12

x^{2} + 8 x + 12 = 5

Move

5

to the left side

x^{2} + 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 7 = 6

x_{1, 2} = \frac{- 8 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 6}{2 \cdot 1}, x_{2} = \frac{- 8 - 6}{2 \cdot 1}

x = \frac{- 8 + 6}{2 \cdot 1} : - 1

x = \frac{- 8 - 6}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 1, x = - 7

- x^{2} - 6 x - 6 = 0

c^{2} - \frac{1}{16} = 0

x^{2} - \frac{4}{3} x = \frac{1}{4}

10 x^{2} - x + 9 = 0

- x^{2} - 11 x - 18 = 0

What are the solutions to the equation (x+6)(x+2)=5 ?
The solutions to the equation (x+6)(x+2)=5 are x=-1,x=-7
Find the zeros of (x+6)(x+2)=5
The zeros of (x+6)(x+2)=5 are x=-1,x=-7