What are the solutions to the equation z^2+26z+37=0 ?

The solutions to the equation z^2+26z+37=0 are z=-13+2sqrt(33),z=-13-2sqrt(33)

Find the zeros of z^2+26z+37=0

The zeros of z^2+26z+37=0 are z=-13+2sqrt(33),z=-13-2sqrt(33)

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z^{2} + 26 z + 37 = 0

z = - 13 + 233, z = - 13 - 233

Decimal Notation

z = - 1.51087 \dots, z = - 24.48912 \dots

Solution steps

z^{2} + 26 z + 37 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 1 \cdot 37}{2 \cdot 1}

2 6^{2} - 4 \cdot 1 \cdot 37 = 433

z_{1, 2} = \frac{- 26 \pm 4 33}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 26 + 4 33}{2 \cdot 1}, z_{2} = \frac{- 26 - 4 33}{2 \cdot 1}

z = \frac{- 26 + 4 33}{2 \cdot 1} : - 13 + 233

z = \frac{- 26 - 4 33}{2 \cdot 1} : - 13 - 233

The solutions to the quadratic equation are:

z = - 13 + 233, z = - 13 - 233

s^{2} + 2 s + 100 = 0

x^{2} + 40 x + 4000 = 0

(x + 1)^{2} - 2 = 3 x + 1

- x^{2} - 6 x - 2 = 0

r^{2} + 2 r + 13 = 0

What are the solutions to the equation z^2+26z+37=0 ?
The solutions to the equation z^2+26z+37=0 are z=-13+2sqrt(33),z=-13-2sqrt(33)
Find the zeros of z^2+26z+37=0
The zeros of z^2+26z+37=0 are z=-13+2sqrt(33),z=-13-2sqrt(33)