What are the solutions to the equation 12x^2-16x=0 ?

The solutions to the equation 12x^2-16x=0 are x= 4/3 ,x=0

Find the zeros of 12x^2-16x=0

The zeros of 12x^2-16x=0 are x= 4/3 ,x=0

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12 x^{2} - 16 x = 0

x = \frac{4}{3}, x = 0

Decimal Notation

x = 1.33333 \dots, x = 0

Solution steps

12 x^{2} - 16 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

(- 16)^{2} - 4 \cdot 12 \cdot 0 = 16

x_{1, 2} = \frac{- ( - 16 ) \pm 16}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 16}{2 \cdot 12}, x_{2} = \frac{- ( - 16 ) - 16}{2 \cdot 12}

x = \frac{- ( - 16 ) + 16}{2 \cdot 12} : \frac{4}{3}

x = \frac{- ( - 16 ) - 16}{2 \cdot 12} : 0

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = 0

x = x^{2} + 5 x - 5

3 t^{2} - 14 t + 16 = 0

x^{2} + 1.5 x + 0.5 = 0

x^{2} - 1 = \frac{1}{2} x + \frac{1}{2}

2 x^{2} - 6 x = - 3

What are the solutions to the equation 12x^2-16x=0 ?
The solutions to the equation 12x^2-16x=0 are x= 4/3 ,x=0
Find the zeros of 12x^2-16x=0
The zeros of 12x^2-16x=0 are x= 4/3 ,x=0