What are the solutions to the equation 9x^2-2x+3=0 ?

The solutions to the equation 9x^2-2x+3=0 are x= 1/9+i(sqrt(26))/9 ,x= 1/9-i(sqrt(26))/9

Find the zeros of 9x^2-2x+3=0

The zeros of 9x^2-2x+3=0 are x= 1/9+i(sqrt(26))/9 ,x= 1/9-i(sqrt(26))/9

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9 x^{2} - 2 x + 3 = 0

x = \frac{1}{9} + i \frac{26}{9}, x = \frac{1}{9} - i \frac{26}{9}

Solution steps

9 x^{2} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 9 \cdot 3}{2 \cdot 9}

Simplify

(- 2)^{2} - 4 \cdot 9 \cdot 3 : 226 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 26 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 26 i}{2 \cdot 9}, x_{2} = \frac{- ( - 2 ) - 2 26 i}{2 \cdot 9}

x = \frac{- ( - 2 ) + 2 26 i}{2 \cdot 9} : \frac{1}{9} + i \frac{26}{9}

x = \frac{- ( - 2 ) - 2 26 i}{2 \cdot 9} : \frac{1}{9} - i \frac{26}{9}

The solutions to the quadratic equation are:

x = \frac{1}{9} + i \frac{26}{9}, x = \frac{1}{9} - i \frac{26}{9}

n^{2} + 7 n + 12 = 0

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3 x^{2} + 5 x - 4 + n = 0

x^{2} - 10 x - 400 = 0

11 x^{2} + 12 = 0

What are the solutions to the equation 9x^2-2x+3=0 ?
The solutions to the equation 9x^2-2x+3=0 are x= 1/9+i(sqrt(26))/9 ,x= 1/9-i(sqrt(26))/9
Find the zeros of 9x^2-2x+3=0
The zeros of 9x^2-2x+3=0 are x= 1/9+i(sqrt(26))/9 ,x= 1/9-i(sqrt(26))/9