What are the solutions to the equation x^2+18x=15 ?

The solutions to the equation x^2+18x=15 are x=-9+4sqrt(6),x=-9-4sqrt(6)

Find the zeros of x^2+18x=15

The zeros of x^2+18x=15 are x=-9+4sqrt(6),x=-9-4sqrt(6)

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x^{2} + 18 x = 15

x = - 9 + 46, x = - 9 - 46

Decimal Notation

x = 0.79795 \dots, x = - 18.79795 \dots

Solution steps

x^{2} + 18 x = 15

Move

15

to the left side

x^{2} + 18 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot (- 15) = 86

x_{1, 2} = \frac{- 18 \pm 8 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 8 6}{2 \cdot 1}, x_{2} = \frac{- 18 - 8 6}{2 \cdot 1}

x = \frac{- 18 + 8 6}{2 \cdot 1} : - 9 + 46

x = \frac{- 18 - 8 6}{2 \cdot 1} : - 9 - 46

The solutions to the quadratic equation are:

x = - 9 + 46, x = - 9 - 46

d = 0.006 (1 - \frac{( ( 1.82 ) - ( d ) ( 1500 ) )}{- 3})^{2}

0 = a (x - 3)^{2} + 1

6 x^{2} + 5 x - 1

p^{2} = 9

(x + 2)^{2} + 11 (x + 2) - 12 = 0

What are the solutions to the equation x^2+18x=15 ?
The solutions to the equation x^2+18x=15 are x=-9+4sqrt(6),x=-9-4sqrt(6)
Find the zeros of x^2+18x=15
The zeros of x^2+18x=15 are x=-9+4sqrt(6),x=-9-4sqrt(6)