What are the solutions to the equation 2x^2+2x-1=x^2+6x-5 ?

The solutions to the equation 2x^2+2x-1=x^2+6x-5 are x=2

Find the zeros of 2x^2+2x-1=x^2+6x-5

The zeros of 2x^2+2x-1=x^2+6x-5 are x=2

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2 x^{2} + 2 x - 1 = x^{2} + 6 x - 5

x = 2

Solution steps

2 x^{2} + 2 x - 1 = x^{2} + 6 x - 5

Move

5

to the left side

2 x^{2} + 2 x + 4 = x^{2} + 6 x

Move

6 x

to the left side

2 x^{2} - 4 x + 4 = x^{2}

Move

x^{2}

to the left side

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

p, (y - p x)^{2} = 1 + p^{2}

x, A = (x + y) (x + y)

x, x^{2} + y^{2} - 4 x - 2 y + 7 = 0

12 x^{2} - 20 x + 6 = 0

a^{2} - 10 a + 21 = 0

What are the solutions to the equation 2x^2+2x-1=x^2+6x-5 ?
The solutions to the equation 2x^2+2x-1=x^2+6x-5 are x=2
Find the zeros of 2x^2+2x-1=x^2+6x-5
The zeros of 2x^2+2x-1=x^2+6x-5 are x=2