What are the solutions to the equation 9b^2+6b=-1 ?

The solutions to the equation 9b^2+6b=-1 are b=-1/3

Find the zeros of 9b^2+6b=-1

The zeros of 9b^2+6b=-1 are b=-1/3

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9 b^{2} + 6 b = - 1

b = - \frac{1}{3}

Decimal Notation

b = - 0.33333 \dots

Solution steps

9 b^{2} + 6 b = - 1

Move

1

to the left side

9 b^{2} + 6 b + 1 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

b_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

b = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

b = - \frac{1}{3}

The solution to the quadratic equation is:

b = - \frac{1}{3}

49 x^{2} = 100

s^{2} = 16

3 x^{2} + 2 x + 5

s^{2} = - 5

2 x^{2} - 7 x + 3 = 0

What are the solutions to the equation 9b^2+6b=-1 ?
The solutions to the equation 9b^2+6b=-1 are b=-1/3
Find the zeros of 9b^2+6b=-1
The zeros of 9b^2+6b=-1 are b=-1/3