What are the solutions to the equation A=y^2-40y ?

The solutions to the equation A=y^2-40y are y=20+sqrt(A+400),y=20-sqrt(A+400)

Find the zeros of A=y^2-40y

The zeros of A=y^2-40y are y=20+sqrt(A+400),y=20-sqrt(A+400)

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A = y^{2} - 40 y

y = 20 + A + 400, y = 20 - A + 400

Solution steps

A = y^{2} - 40 y

Switch sides

y^{2} - 40 y = A

Move

A

to the left side

y^{2} - 40 y - A = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 1 \cdot ( - A )}{2 \cdot 1}

Simplify

(- 40)^{2} - 4 \cdot 1 \cdot (- A) : 2 400 + A

y_{1, 2} = \frac{- ( - 40 ) \pm 2 400 + A}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 40 ) + 2 400 + A}{2 \cdot 1}, y_{2} = \frac{- ( - 40 ) - 2 400 + A}{2 \cdot 1}

y = \frac{- ( - 40 ) + 2 400 + A}{2 \cdot 1} : 20 + A + 400

y = \frac{- ( - 40 ) - 2 400 + A}{2 \cdot 1} : 20 - A + 400

The solutions to the quadratic equation are:

y = 20 + A + 400, y = 20 - A + 400

X^{2} + 7 X = - 10

5 0^{2} = 1 4^{2} + x^{2}

3 x^{2} - x^{2} = 0

3 x^{2} - 12 x - 45 - 243 = 0

x^{2} - 8 x - 3

What are the solutions to the equation A=y^2-40y ?
The solutions to the equation A=y^2-40y are y=20+sqrt(A+400),y=20-sqrt(A+400)
Find the zeros of A=y^2-40y
The zeros of A=y^2-40y are y=20+sqrt(A+400),y=20-sqrt(A+400)