What are the solutions to the equation 2x^2+5x-20=0 ?

The solutions to the equation 2x^2+5x-20=0 are x=(-5+sqrt(185))/4 ,x=(-5-sqrt(185))/4

Find the zeros of 2x^2+5x-20=0

The zeros of 2x^2+5x-20=0 are x=(-5+sqrt(185))/4 ,x=(-5-sqrt(185))/4

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2 x^{2} + 5 x - 20 = 0

x = \frac{- 5 + 185}{4}, x = \frac{- 5 - 185}{4}

Decimal Notation

x = 2.15036 \dots, x = - 4.65036 \dots

Solution steps

2 x^{2} + 5 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 20) = 185

x_{1, 2} = \frac{- 5 \pm 185}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 185}{2 \cdot 2}, x_{2} = \frac{- 5 - 185}{2 \cdot 2}

x = \frac{- 5 + 185}{2 \cdot 2} : \frac{- 5 + 185}{4}

x = \frac{- 5 - 185}{2 \cdot 2} : \frac{- 5 - 185}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 185}{4}, x = \frac{- 5 - 185}{4}

x^{2} - x - 2 = 0

4 (x - 6)^{2} = 100

(x + 2) (x - 2) = 32

(x + 2)^{2} - 2 (x + 2) - 15 = 0

x^{2} + x - 12

What are the solutions to the equation 2x^2+5x-20=0 ?
The solutions to the equation 2x^2+5x-20=0 are x=(-5+sqrt(185))/4 ,x=(-5-sqrt(185))/4
Find the zeros of 2x^2+5x-20=0
The zeros of 2x^2+5x-20=0 are x=(-5+sqrt(185))/4 ,x=(-5-sqrt(185))/4