What are the solutions to the equation c^2-18c=-65 ?

The solutions to the equation c^2-18c=-65 are c=13,c=5

Find the zeros of c^2-18c=-65

The zeros of c^2-18c=-65 are c=13,c=5

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c^{2} - 18 c = - 65

c = 13, c = 5

Solution steps

c^{2} - 18 c = - 65

Move

65

to the left side

c^{2} - 18 c + 65 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 65}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 65 = 8

c_{1, 2} = \frac{- ( - 18 ) \pm 8}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 18 ) + 8}{2 \cdot 1}, c_{2} = \frac{- ( - 18 ) - 8}{2 \cdot 1}

c = \frac{- ( - 18 ) + 8}{2 \cdot 1} : 13

c = \frac{- ( - 18 ) - 8}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

c = 13, c = 5

81 x^{2} = 64

x^{2} + 9 x - 400 = 0

8 (3 x - 7)^{2} + 2 (3 x - 7) - 45 = 0

6 x^{2} = - 9 x

0 = 3 x^{2} + 10 x + 3

What are the solutions to the equation c^2-18c=-65 ?
The solutions to the equation c^2-18c=-65 are c=13,c=5
Find the zeros of c^2-18c=-65
The zeros of c^2-18c=-65 are c=13,c=5