What are the solutions to the equation 8=-3n^2+10n ?

The solutions to the equation 8=-3n^2+10n are n= 4/3 ,n=2

Find the zeros of 8=-3n^2+10n

The zeros of 8=-3n^2+10n are n= 4/3 ,n=2

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8 = - 3 n^{2} + 10 n

n = \frac{4}{3}, n = 2

Decimal Notation

n = 1.33333 \dots, n = 2

Solution steps

8 = - 3 n^{2} + 10 n

Switch sides

- 3 n^{2} + 10 n = 8

Move

8

to the left side

- 3 n^{2} + 10 n - 8 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 3 ) ( - 8 )}{2 ( - 3 )}

1 0^{2} - 4 (- 3) (- 8) = 2

n_{1, 2} = \frac{- 10 \pm 2}{2 ( - 3 )}

Separate the solutions

n_{1} = \frac{- 10 + 2}{2 ( - 3 )}, n_{2} = \frac{- 10 - 2}{2 ( - 3 )}

n = \frac{- 10 + 2}{2 ( - 3 )} : \frac{4}{3}

n = \frac{- 10 - 2}{2 ( - 3 )} : 2

The solutions to the quadratic equation are:

n = \frac{4}{3}, n = 2

\frac{1}{5} x^{2} + 2 x + \frac{2}{3} = 0

3 x^{2} - 9 x + 9 = 0

3 x^{2} + 7 x = 0

204 x - 6 x^{2} = 0

2 x^{2} - 7 x - 4 = 45

What are the solutions to the equation 8=-3n^2+10n ?
The solutions to the equation 8=-3n^2+10n are n= 4/3 ,n=2
Find the zeros of 8=-3n^2+10n
The zeros of 8=-3n^2+10n are n= 4/3 ,n=2