What are the solutions to the equation solvefor y,4x^2+y^2=4 ?

The solutions to the equation solvefor y,4x^2+y^2=4 are y=2sqrt(1-x^2),y=-2sqrt(1-x^2)

Find the zeros of solvefor y,4x^2+y^2=4

The zeros of solvefor y,4x^2+y^2=4 are y=2sqrt(1-x^2),y=-2sqrt(1-x^2)

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solve for

y, 4 x^{2} + y^{2} = 4

y = 2 1 - x^{2}, y = - 2 1 - x^{2}

Solution steps

4 x^{2} + y^{2} = 4

Move

4 x^{2}

to the right side

y^{2} = 4 - 4 x^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 4 - 4 x^{2}, y = - 4 - 4 x^{2}

Simplify

4 - 4 x^{2} : 2 1 - x^{2}

Simplify

- 4 - 4 x^{2} : - 2 1 - x^{2}

y = 2 1 - x^{2}, y = - 2 1 - x^{2}

x^{2} - 20 x + 12 = 0

a^{2} + 14 a - 51 = 0

3 x^{2} - 6 x - 240 = 0

- 5 x^{2} + 7 x = - 3

x^{2} - 5 x - 21 = 0

What are the solutions to the equation solvefor y,4x^2+y^2=4 ?
The solutions to the equation solvefor y,4x^2+y^2=4 are y=2sqrt(1-x^2),y=-2sqrt(1-x^2)
Find the zeros of solvefor y,4x^2+y^2=4
The zeros of solvefor y,4x^2+y^2=4 are y=2sqrt(1-x^2),y=-2sqrt(1-x^2)