What are the solutions to the equation -3x^2+6x+6=0 ?

The solutions to the equation -3x^2+6x+6=0 are x=1-sqrt(3),x=1+sqrt(3)

Find the zeros of -3x^2+6x+6=0

The zeros of -3x^2+6x+6=0 are x=1-sqrt(3),x=1+sqrt(3)

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- 3 x^{2} + 6 x + 6 = 0

x = 1 - 3, x = 1 + 3

Decimal Notation

x = - 0.73205 \dots, x = 2.73205 \dots

Solution steps

- 3 x^{2} + 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 6}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 6 = 63

x_{1, 2} = \frac{- 6 \pm 6 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 6 3}{2 ( - 3 )}, x_{2} = \frac{- 6 - 6 3}{2 ( - 3 )}

x = \frac{- 6 + 6 3}{2 ( - 3 )} : 1 - 3

x = \frac{- 6 - 6 3}{2 ( - 3 )} : 1 + 3

The solutions to the quadratic equation are:

x = 1 - 3, x = 1 + 3

x^{2} = \frac{169}{25}

5 z^{2} - 15 = 0

x, u = 1 - x^{2}

- 16 x^{2} + 266 x + 102 = 0

5 x^{2} = 2 x + 6

What are the solutions to the equation -3x^2+6x+6=0 ?
The solutions to the equation -3x^2+6x+6=0 are x=1-sqrt(3),x=1+sqrt(3)
Find the zeros of -3x^2+6x+6=0
The zeros of -3x^2+6x+6=0 are x=1-sqrt(3),x=1+sqrt(3)