What are the solutions to the equation w^2-2sqrt(2)w+2=0 ?

The solutions to the equation w^2-2sqrt(2)w+2=0 are w=sqrt(2)

Find the zeros of w^2-2sqrt(2)w+2=0

The zeros of w^2-2sqrt(2)w+2=0 are w=sqrt(2)

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w^{2} - 22 w + 2 = 0

w = 2

Decimal Notation

w = 1.41421 \dots

Solution steps

w^{2} - 22 w + 2 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 2 2 ) \pm ( - 2 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 22)^{2} - 4 \cdot 1 \cdot 2 = 0

w_{1, 2} = \frac{- ( - 2 2 ) \pm 0}{2 \cdot 1}

w = \frac{- ( - 2 2 )}{2 \cdot 1}

\frac{- ( - 2 2 )}{2 \cdot 1} = 2

w = 2

The solution to the quadratic equation is:

w = 2

x^{2} + 8 x - 17 = 9

x^{2} = \frac{3}{3}

7 + x (x) = 120

(x - 1)^{2} = 2 x - 3

12 x^{2} + 5 x - 72 = 0

What are the solutions to the equation w^2-2sqrt(2)w+2=0 ?
The solutions to the equation w^2-2sqrt(2)w+2=0 are w=sqrt(2)
Find the zeros of w^2-2sqrt(2)w+2=0
The zeros of w^2-2sqrt(2)w+2=0 are w=sqrt(2)