What are the solutions to the equation w^2+4w+3=0 ?

The solutions to the equation w^2+4w+3=0 are w=-1,w=-3

Find the zeros of w^2+4w+3=0

The zeros of w^2+4w+3=0 are w=-1,w=-3

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w^{2} + 4 w + 3 = 0

w = - 1, w = - 3

Solution steps

w^{2} + 4 w + 3 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 3 = 2

w_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 4 + 2}{2 \cdot 1}, w_{2} = \frac{- 4 - 2}{2 \cdot 1}

w = \frac{- 4 + 2}{2 \cdot 1} : - 1

w = \frac{- 4 - 2}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

w = - 1, w = - 3

x^{2} + 2 x - 7

(x - 1)^{2} = 40

v, e = \frac{1}{2} \cdot m \cdot v^{2} + m \cdot g \cdot h

21 x^{2} = 4 - 5 x

19 x^{2} = 8 x

What are the solutions to the equation w^2+4w+3=0 ?
The solutions to the equation w^2+4w+3=0 are w=-1,w=-3
Find the zeros of w^2+4w+3=0
The zeros of w^2+4w+3=0 are w=-1,w=-3