What are the solutions to the equation (4x+3)^2+11=-17 ?

The solutions to the equation (4x+3)^2+11=-17 are x=-3/4+i(sqrt(7))/2 ,x=-3/4-i(sqrt(7))/2

Find the zeros of (4x+3)^2+11=-17

The zeros of (4x+3)^2+11=-17 are x=-3/4+i(sqrt(7))/2 ,x=-3/4-i(sqrt(7))/2

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(4 x + 3)^{2} + 11 = - 17

x = - \frac{3}{4} + i \frac{7}{2}, x = - \frac{3}{4} - i \frac{7}{2}

Solution steps

(4 x + 3)^{2} + 11 = - 17

Move

11

to the right side

(4 x + 3)^{2} = - 28

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 3 = - 28 : x = - \frac{3}{4} + i \frac{7}{2}

Solve

4 x + 3 = - - 28 : x = - \frac{3}{4} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{4} + i \frac{7}{2}, x = - \frac{3}{4} - i \frac{7}{2}

x^{2} + 12 x + 46 = 0

- 4.9 x^{2} + 24.5 x + 2 = 0

- 4.9 t^{2} + 12 t + 600 = 0

(k - 4)^{2} = - 3

p^{2} + 6 p = 0

What are the solutions to the equation (4x+3)^2+11=-17 ?
The solutions to the equation (4x+3)^2+11=-17 are x=-3/4+i(sqrt(7))/2 ,x=-3/4-i(sqrt(7))/2
Find the zeros of (4x+3)^2+11=-17
The zeros of (4x+3)^2+11=-17 are x=-3/4+i(sqrt(7))/2 ,x=-3/4-i(sqrt(7))/2