What are the solutions to the equation 3+4x+x^2=0 ?

The solutions to the equation 3+4x+x^2=0 are x=-1,x=-3

Find the zeros of 3+4x+x^2=0

The zeros of 3+4x+x^2=0 are x=-1,x=-3

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3 + 4 x + x^{2} = 0

x = - 1, x = - 3

Solution steps

3 + 4 x + x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2}{2 \cdot 1}

x = \frac{- 4 + 2}{2 \cdot 1} : - 1

x = \frac{- 4 - 2}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

4 y^{2} = 12 y

(5 x - 3) (x - 5) = 0

x^{2} - 8 x + 3 = 2

2 x - 2 = x^{2} + 7 x - 38

x^{2} - 10 x = - 41

What are the solutions to the equation 3+4x+x^2=0 ?
The solutions to the equation 3+4x+x^2=0 are x=-1,x=-3
Find the zeros of 3+4x+x^2=0
The zeros of 3+4x+x^2=0 are x=-1,x=-3