What are the solutions to the equation 4b^2-4b+7=66 ?

The solutions to the equation 4b^2-4b+7=66 are b=(1+2sqrt(15))/2 ,b=(1-2sqrt(15))/2

Find the zeros of 4b^2-4b+7=66

The zeros of 4b^2-4b+7=66 are b=(1+2sqrt(15))/2 ,b=(1-2sqrt(15))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 b^{2} - 4 b + 7 = 66

b = \frac{1 + 2 15}{2}, b = \frac{1 - 2 15}{2}

Decimal Notation

b = 4.37298 \dots, b = - 3.37298 \dots

Solution steps

4 b^{2} - 4 b + 7 = 66

Move

66

to the left side

4 b^{2} - 4 b - 59 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 59 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 59) = 815

b_{1, 2} = \frac{- ( - 4 ) \pm 8 15}{2 \cdot 4}

Separate the solutions

b_{1} = \frac{- ( - 4 ) + 8 15}{2 \cdot 4}, b_{2} = \frac{- ( - 4 ) - 8 15}{2 \cdot 4}

b = \frac{- ( - 4 ) + 8 15}{2 \cdot 4} : \frac{1 + 2 15}{2}

b = \frac{- ( - 4 ) - 8 15}{2 \cdot 4} : \frac{1 - 2 15}{2}

The solutions to the quadratic equation are:

b = \frac{1 + 2 15}{2}, b = \frac{1 - 2 15}{2}

r, 0.0119 = \frac{1}{2} (326) r^{2}

6.28 (\frac{4 - x}{2})^{2} = 20.12

(x - 4) (x - 10) = 0

2 x^{2} - 6 = x^{2} + 7 x - 9

4 (x + 5)^{2} - 49 = 0

What are the solutions to the equation 4b^2-4b+7=66 ?
The solutions to the equation 4b^2-4b+7=66 are b=(1+2sqrt(15))/2 ,b=(1-2sqrt(15))/2
Find the zeros of 4b^2-4b+7=66
The zeros of 4b^2-4b+7=66 are b=(1+2sqrt(15))/2 ,b=(1-2sqrt(15))/2