What are the solutions to the equation b^2-18b-24=9-4b ?

The solutions to the equation b^2-18b-24=9-4b are b=7+sqrt(82),b=7-sqrt(82)

Find the zeros of b^2-18b-24=9-4b

The zeros of b^2-18b-24=9-4b are b=7+sqrt(82),b=7-sqrt(82)

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b^{2} - 18 b - 24 = 9 - 4 b

b = 7 + 82, b = 7 - 82

Decimal Notation

b = 16.05538 \dots, b = - 2.05538 \dots

Solution steps

b^{2} - 18 b - 24 = 9 - 4 b

Move

4 b

to the left side

b^{2} - 14 b - 24 = 9

Move

9

to the left side

b^{2} - 14 b - 33 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 33 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 33) = 282

b_{1, 2} = \frac{- ( - 14 ) \pm 2 82}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 14 ) + 2 82}{2 \cdot 1}, b_{2} = \frac{- ( - 14 ) - 2 82}{2 \cdot 1}

b = \frac{- ( - 14 ) + 2 82}{2 \cdot 1} : 7 + 82

b = \frac{- ( - 14 ) - 2 82}{2 \cdot 1} : 7 - 82

The solutions to the quadratic equation are:

b = 7 + 82, b = 7 - 82

x (x - 17) = - 60

6 x^{2} + 19 x = 20

46.39 = 46.8 + 30.2 t - 4.9 t^{2}

6 (x + 2)^{2} + 7 (x + 2) - 3 = 0

9 x^{2} - 17 x - 85 = 0

What are the solutions to the equation b^2-18b-24=9-4b ?
The solutions to the equation b^2-18b-24=9-4b are b=7+sqrt(82),b=7-sqrt(82)
Find the zeros of b^2-18b-24=9-4b
The zeros of b^2-18b-24=9-4b are b=7+sqrt(82),b=7-sqrt(82)