What are the solutions to the equation x^2+63x-992=0 ?

The solutions to the equation x^2+63x-992=0 are x=(-63+sqrt(7937))/2 ,x=(-63-sqrt(7937))/2

Find the zeros of x^2+63x-992=0

The zeros of x^2+63x-992=0 are x=(-63+sqrt(7937))/2 ,x=(-63-sqrt(7937))/2

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x^{2} + 63 x - 992 = 0

x = \frac{- 63 + 7937}{2}, x = \frac{- 63 - 7937}{2}

Decimal Notation

x = 13.04492 \dots, x = - 76.04492 \dots

Solution steps

x^{2} + 63 x - 992 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 63 \pm 6 3 ^{2} - 4 \cdot 1 \cdot ( - 992 )}{2 \cdot 1}

6 3^{2} - 4 \cdot 1 \cdot (- 992) = 7937

x_{1, 2} = \frac{- 63 \pm 7937}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 63 + 7937}{2 \cdot 1}, x_{2} = \frac{- 63 - 7937}{2 \cdot 1}

x = \frac{- 63 + 7937}{2 \cdot 1} : \frac{- 63 + 7937}{2}

x = \frac{- 63 - 7937}{2 \cdot 1} : \frac{- 63 - 7937}{2}

The solutions to the quadratic equation are:

x = \frac{- 63 + 7937}{2}, x = \frac{- 63 - 7937}{2}

2 x^{2} + 24 x + 8 = 0

(3 x + 6) (6 x + 5) = 0

(3 x - 1) (2 x + 1) = 0

(x + 3)^{2} = 10 (3 x - 11)

t, s = - 16 t^{2} + 100 t

What are the solutions to the equation x^2+63x-992=0 ?
The solutions to the equation x^2+63x-992=0 are x=(-63+sqrt(7937))/2 ,x=(-63-sqrt(7937))/2
Find the zeros of x^2+63x-992=0
The zeros of x^2+63x-992=0 are x=(-63+sqrt(7937))/2 ,x=(-63-sqrt(7937))/2