What are the solutions to the equation m^2+12=0 ?

The solutions to the equation m^2+12=0 are m=2sqrt(3)i,m=-2sqrt(3)i

Find the zeros of m^2+12=0

The zeros of m^2+12=0 are m=2sqrt(3)i,m=-2sqrt(3)i

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m^{2} + 12 = 0

m = 23 i, m = - 23 i

Solution steps

m^{2} + 12 = 0

Move

12

to the right side

m^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = - 12, m = - - 12

- 12 = 23 i

- - 12 = - 23 i

m = 23 i, m = - 23 i

x^{2} + 3 x + 8

x, f = 4 x^{2} - 4 x y + y^{2}

x^{2} + 3 x - 7

x^{2} + 0.15 x - 0.225 = 0

x, - x^{2} - y^{2} = 0

What are the solutions to the equation m^2+12=0 ?
The solutions to the equation m^2+12=0 are m=2sqrt(3)i,m=-2sqrt(3)i
Find the zeros of m^2+12=0
The zeros of m^2+12=0 are m=2sqrt(3)i,m=-2sqrt(3)i